[Solved] 50- An Earth Satellite Moves In A Circular Orbit At A Speed... ~ BestNews

Friday, April 9, 2021

[Solved] 50- An Earth Satellite Moves In A Circular Orbit At A Speed...

April 09, 2021 / by NewsGeek / with No comments /

The time of one revolution and its centripetal acceleration are 1.05 × 10⁴ s and 3.7 m/s². Step-by-step explanation The time taken by the satellite to complete one revolution is given by the formula: T = (2πr)/v → (equation 1). On applying Newton's second law, we getWhat is its orbital period?... What Is Its Orbital Period? This problem has been solved!The guideline is parallel to the ground. Find the speed of the plane such that the plane and the satellite have the same centripetal acceleration' and find homework help for other Science questions at eNotes. A satellite moves in a circular orbit around Earth at a speed of 4988 m/s.Its altitudeSuppose an earth satellite, revolving in a circular orbit experiences a resistance due to cosmic dust. Then. This question has multiple correct options. View Answer. A satellite of mass 1000kg is supposed to orbit the earth at a height of 2000km above the earth's surface. Find its kinetic energy.1. A satellite moves in a circular orbit around Earth at a speed of 5 000 m/s. Determine (a) the satellite's altitude above the surface of Earth and (b) A communications satellite with a mass of 520 kg is in a circular orbit about the Earth. The radius of the orbit is 35,000 km as measured from the...

Solved: An Earth Satellite Moves In A Circular Orbit At... | Chegg.com

An object of mass 'm' is ejected from the satellite such that it just escapes form the gravitational pull of the earth. For particles of equal massses M move along a circle of radius R under th action of their mutual gravitational attraction. Find the speed of each particle.v is the orbital speed, which we know is 7,000 m/s. r = 6.67428 x 10^-11 x 5.9742 x 10^24/7,000^2. r = 8,137,445 meters from the center of the Earth. Which one of the following statements about circular motion is correct? model airplane is tethered to a post and held by a fine line.It flies in a horizontal...An artificial Earth satellite in an elliptical orbit has its greatest speed when it is at what location? nearest the Earth farthest from the Earth between Earth and moon between Earth and sun. A 1500 kg car rounds an unbanked curve with a radius of 52 m at a speed of 12 m/s.39. Calculate the velocity of a satellite moving in a stable circular orbit about the Earth at a height of 3600 km? 3600 km = 3,600,000 m = 3.6x106 m When a small object orbits an object with much greater mass, the gravitational attraction between the two objects causes both objects to accelerate toward...

A satellite moves on a circular earth orbit that has a radius... | eNotes

A satellite moves on a circular earth orbit that has a radius of 6.68E+6 m. A model airplane is flying on a 16.3 m guideline in a horizontal circle.Determining the orbital speed and orbital period of a satellite is much easier for circular orbits, so we make that assumption in the derivation that follows. Consider a satellite of mass m in a circular orbit about Earth at distance r from the center of Earth (Figure 13.12). It has centripetal acceleration...What is its orbital period?" is broken down into a number of easy to follow steps, and 19 words. The full step-by-step solution to problem: 13.57 from chapter: 13 was answered by , our top Physics solution expert on 12/28/17, 08 13.6: A satellite orbits the earth with constant speed at a height aboveOrbital Speed Equation. Consider a satellite with mass Msat orbiting a central body with a mass of mass MCentral. If the satellite moves in circular motion, then the net centripetal force acting upon this orbiting A satellite wishes to orbit the earth at a height of 100 km (approximately 60 miles)...Explanation: The reference for Orbital Speed gives us the following equation: #v_0= sqrt((GM)/r)#. Where, #M# is the mass of the Earth #(5.972 xx 10^24" kg")#

First we want to to find the gap of the satellite from the planet.

r = GM/v^2

r is the space of the satellite from the center of Earth in meters

G is newtons consistent, 6.67428 x 10^-11

M is the mass of Earth, 5.9742 x 10^24

v is the orbital speed, which we all know is 7,000 m/s

r = 6.67428 x 10^-11 x 5.9742 x 10^24/7,000^2

r = 8,137,445 meters from the center of the Earth

and : 8,137,445 - 6,378,100 = 1,749,345 meters from the skin of the Earth

Now that we all know the gap we will be able to calculate the orbital duration.

Time = Distance/speed

distance is the circumference of the orbit, 2π x 8,137,445 = 51,129,074 meters